Interference of sound waves

 

Many students are apparently confused about how to deal with interference phenomena.  Before discussing waves and interference, there are a few important definitions, facts and relationships that must become totally familiar to you.  For this purpose, we use sound waves as the example.  All waves you need to know about behave the same way, so that what is learned about interference in sound waves can be carried over to apply to interference in light waves. 

 

Assume that we have an electronic oscillator that generates a specific sinusoidal frequency f in cycles per second (Hertz).  When a speaker is connected to this oscillator, the speaker cone is driven back and forth.  As a result, a sound wave is emitted as a pure tone at the given frequency f.  The sound wave propagates through air as a sinusoidally varying pressure wave.  The wave travels with velocity v and has a wavelength λ that satisfies the relationship λ = v/f.    Since the frequency f has the units of cycles/second, the inverse of the frequency must have the units seconds/cycle. The quantity 1/f is called the period T, i.e., the time interval for one cycle.  As the wave falls incident on a listening device, such as your eardrum, the oscillating pressure is processed by your inner ear and interpreted by your brain as sound at the frequency f.

 

                Now assume that two speakers are connected to the same oscillator.  What this means is that when one speaker cone is moving outward during its vibrational motion, the other one is performing the exact same motion. The two speakers are said to be in phase with each other.  This implies that the two emitted waves at the respective positions of the speakers are exactly in phase with each other.  The intensity of the two sounds can also be adjusted so that they are the same or nearly so, although is not a requirement.

 

But now let us look at the consequences of placing a receiver that “hears” the sound from each speaker simultaneously at a specific point in space.  To understand the effect, we need only know what happens when two waves are superimposed on each other.  Experiment shows that when two waves meet at the same point in space, the two waves simply add algebraically point-by-point.  Sound waves are said to obey the superposition principle.  But when waves travel different distances to merge at a given point in space, any phase relationship they had at the speakers is modified.  The new phase relationship can be determined easily if we take into account the fact that the sound travels at a velocity v.  If a receiver is located equidistant from each speaker, then the sound from each speaker takes exactly the same time to reach the receiver.  Since each wave oscillates at the same frequency and travels at the same speed, the phase at the position of the receiver is maintained exactly the same as at the speakers.

 

Next, suppose our two identical speakers are positioned such that speaker A is farther from the receiver than speaker B by an amount Δs.  This means that a given pulse from A takes longer to reach the receiver than the same pulse from B, and the delay time is Δt = Δs/v.  In general this delay will cause the two waves to be out of phase with respect to each other when they reach the receiver.  But if Δt is exactly one period, then by the very definition of a period T, the two waves will be back in step.  This is equivalent to saying that sin(z) = sin(z + 360o). A shift by one period or by any whole number of periods leaves the phase unchanged.  Times can be restated in terms of distances.  Thus, a shift of one period in times is equivalent to a difference in distance Δs = vT = v/f = λ.  Of course, a shift in two periods is equivalent to a difference of Δs = 2λ, etc.

 

In summary, if two sources are in phase with each other, and one source is an integral number of wavelengths farther from the listener than the other source, the waves will be in phase with each other at the position of the listener, and the sound will be relatively loud (constructive interference).  Similarly, if two sources are in phase with each other, and one source is half of a wavelength farther from the listener than the other source (or 3/2 wavelength, 5/2 wavelength, etc.), the waves will be out of phase with each other at the position of the listener, and the sound will be relatively soft (destructive interference).

 

This summary is the basis of essentially all the problems in the chapter 28!