Step 1: Label currents using point rule | I2 = 3I1 - 5 -> I2 = -2A | |
Step 2: Write loop rule equations | 0 = -12 + I1 - 5.5(3I1-5) | |
0 = - 1V - (I1-I2)1 + 6V - I12 | 0 = -12 + 27.5 + I1 - 16.5I1 | |
0 = - I23 - 12V - I21.5 + (I1-I2)1 | 0 = 15.5 - 15.5I1 -> I1 = 1A | |
Step 3: Solve | Step 4: Check point and loop rules | |
0 = 5 - 3 I1 + I2 | 0 = -1 -3 +6 -2 (left loop) | |
0 = -12 + I1 - 5.5I2 |