Home Back NextPage PrevPage LastPage FirstPage Contents Mail Copyright
Find the current:
  1. Label currents
  2. Use voltage drop around loop = 0
  3. Solve
A -> B: +1.5V - 2 Ohms I
B -> C: -1.5V - 1 Ohms I
C -> D: +1.5V - 3 Ohms I
D -> A: +1.5V
Net: 0 = 3V - 6 Ohms I -> I = 0.5A